7x^(2/3)-48x^(1/3)-7=0

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Solution for 7x^(2/3)-48x^(1/3)-7=0 equation: 


x in (-oo:+oo)

7*x^(2/3)-(48*x^(1/3))-7 = 0

7*x^(2/3)-48*x^(1/3)-7 = 0

t_1 = x^(1/3)

7*t_1^2-48*t_1^1-7 = 0

7*t_1^2-48*t_1-7 = 0

DELTA = (-48)^2-(-7*4*7)

DELTA = 2500

DELTA > 0

t_1 = (2500^(1/2)+48)/(2*7) or t_1 = (48-2500^(1/2))/(2*7)

t_1 = 7 or t_1 = -1/7

t_1 = -1/7

x^(1/3)+1/7 = 0

1*x^(1/3) = -1/7 // : 1

x^(1/3) = -1/7

( -1/7 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 7

x^(1/3)-7 = 0

1*x^(1/3) = 7 // : 1

x^(1/3) = 7

x^(1/3) = 7 // ^ 3

x = 343

x = 343

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